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2x^2+6x+4=24=0
We move all terms to the left:
2x^2+6x+4-(24)=0
We add all the numbers together, and all the variables
2x^2+6x-20=0
a = 2; b = 6; c = -20;
Δ = b2-4ac
Δ = 62-4·2·(-20)
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{196}=14$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-14}{2*2}=\frac{-20}{4} =-5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+14}{2*2}=\frac{8}{4} =2 $
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